Q.)Let n!=1*2*3*4*5……*n for integer n≥1.If p=1!+(2*2!)+(3*3!)……+(10*10!),then p+2 when divided by 11! Leaves a remainder of (i)10 (ii)0 (iii)7 (iv)1 [Factorial , Remainder when divided by 11 , Remainder Theorem,MBA Questions,Number System] Solution: Given, p=1!+(2*2!)+(3*3!)……+(10*10!) Now, each term can also be written as 1*1! =2! – 1! 2*2! = 3! – 2! 3*3! = 4! – … Continue reading
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